lab #1 mortar

mix 2, mortar - no coarse aggregate: what we should have done

waterContent=387u"lb/yd^3"
airRatio=2.5/100
wcRatio=0.5
coarseAggRatio=0.5
correctMortarBatch=BatchFromRatios(387u"lb/yd^3", 0.5, 0.0;totalVolume=volume,airRatio=2.5/100)

batch per 11.939716572159998 L
water = 2.7413347473614076 kg
cement = 5.482669494722815 kg
coarse = 0.0 kg
fine = 20.030684304409093 kg
total weight = 28.254688546493316 kg
total volume = 11.939716572159998 L
w/c ratio = 0.5
water content per m^3 = 229.59797502676201 kg m^-3

but i messed up the calculation of fine aggregate and we ended up with

incorrectMortarBatch =Batch(
BatchComponent{Water}(2.741u"kg"),
BatchComponent{Cement}(5.48u"kg"),
BatchComponent{Coarse}(0.0u"kg"),
BatchComponent{Fine}(3.3u"kg"),
BatchComponent{Air}(0u"m^3"))

batch per 5.65925396825397 L
water = 2.741 kg
cement = 5.48 kg
coarse = 0.0 kg
fine = 3.3 kg
total weight = 11.521 kg
total volume = 5.65925396825397 L
w/c ratio = 0.5001824817518248
water content per m^3 = 484.33945805858076 kg m^-3

Note that this is about 2x the correct water content!!! learning experience . png

added additional 1kg of cement +1.5kg of fine aggregate

modifiedMortarBatch = incorrectMortarBatch+BatchComponent{Cement}(1.0u"kg")+BatchComponent{Fine}(1.5u"kg")

batch per 6.512428571428572 L
water = 2.741 kg
cement = 6.48 kg
coarse = 0.0 kg
fine = 4.8 kg
total weight = 14.021 kg
total volume = 6.512428571428572 L
w/c ratio = 0.42299382716049383
water content per m^3 = 420.88753372672033 kg m^-3

we conducted a slump test -> 165mm = 6.5in which is quite loose, definitely the problem is not enough sand!